So term number 6 is called x6 (which equals 8).
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Example: the 8th term is
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So we can write the rule:
xn = xn−1 + xn−2
where:
Rules like this are called recursive formulas.
To use a recursive formula we also need to know the first few terms. For Fibonacci we start with x0 = 0 and x1 = 1
And here is a surprise.
When we take any two successive (one after the other) Fibonacci Numbers, their ratio is very close to the Golden Ratio "φ" which is approximately 1.618034...
The Golden Ratio is found in art, architecture, and nature.
In fact, the bigger the pair of Fibonacci Numbers, the closer the approximation. Let us try a few:
|
a |
b |
b / a |
|
|---|---|---|---|
|
2 |
3 |
1.5 | |
|
3 |
5 |
1.666666666... | |
|
5 |
8 |
1.6 | |
|
8 |
13 |
1.625 | |
|
... |
... |
... | |
|
144 |
233 |
1.618055556... | |
|
233 |
377 |
1.618025751... | |
|
... |
... |
... |
Try some start values yourself:
It can take longer to get good values, but it shows that not just the Fibonacci Sequence can do this!
And even more surprising is that we can calculate any Fibonacci Number using the Golden Ratio:
xn = φn − (1−φ)n√5
The answer comes out as a whole number, exactly equal to the addition of the previous two terms.
x6 = (1.618034...)6 − (1−1.618034...)6√5
When I used a calculator on this (only entering the Golden Ratio to 6 decimal places) I got the answer 8.00000033 , a more accurate calculation would be closer to 8.
Try n=12 and see what you get.
You can also calculate a Fibonacci Number by multiplying the previous Fibonacci Number by the Golden Ratio and then rounding (works for numbers above 1):
It will be 8 times φ:
8φ = 8 × 1.618034...
= 12.94427...
= 13 (rounded)
The sequence goes even, odd, odd, even, odd, odd, even, odd, odd, ... :
| 0 | 1 | 1 | 2 | 3 | 5 | 8 | 13 | 21 | 34 | 55 | 89 | 144 | 233 | 377 | 610 | ... |
Why?
Because adding two odd numbers produces an even number, but adding even and odd (in any order) produces an odd number.
Starting the sequence with 2 and 1 we get the "Lucas Numbers". They get closer and closer to the powers (exponents) of the Golden Ratio:
| Lucas Number |
n | φn |
|---|---|---|
| 2 | 0 | 1.0000... |
| 1 | 1 | 1.6180... |
| 3 | 2 | 2.6180... |
| 4 | 3 | 4.2361... |
| 7 | 4 | 6.8541... |
| 11 | 5 | 11.0902... |
| 18 | 6 | 17.9443... |
| 29 | 7 | 29.0344... |
| 47 | 8 | 46.9787... |
| 76 | 9 | 76.0132... |
| 123 | 10 | 122.9919... |
| 199 | 11 | 199.0050... |
| ... | ... | ... |
For example, the 15th Lucas Number is approximately φ15 = 1364.0007..., so is exactly 1364. Try it yourself!
| n = | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | ... |
| xn = | 0 | 1 | 1 | 2 | 3 | 5 | 8 | 13 | 21 | 34 | 55 | 89 | 144 | 233 | 377 | 610 | ... |
There is an interesting pattern:
And so on (every nth number is a multiple of xn).
Notice the first few digits (0, 1, 1, 2, 3, 5) are the Fibonacci sequence?
In a way they all are, except multiple digit numbers (13, 21, and so on) overlap, like this:
| 0.0 |
| 0.01 |
| 0.001 |
| 0.0002 |
| 0.00003 |
| 0.000005 |
| 0.0000008 |
| 0.00000013 |
| 0.000000021 |
| ... and so on ... |
| 0.011235955056179775... = 1/89 |
by Rod Pierce
The sequence works below zero also, like this:
| n = | ... | −6 | −5 | −4 | −3 | −2 | −1 | 0 | 1 | 2 | 3 | 4 | 5 | 6 | ... |
| xn = | ... | −8 | 5 | −3 | 2 | −1 | 1 | 0 | 1 | 1 | 2 | 3 | 5 | 8 | ... |
(Prove to yourself that each number is found by adding up the two numbers before it!)
In fact the sequence below zero has the same numbers as the sequence above zero, except they follow a +-+- ... pattern. It can be written like this:
x−n = (−1)n+1 xn
Which says term "−n" is equal to (−1)n+1 times term "n", and the value (−1)n+1 neatly makes the correct +1, −1, +1, −1, ... pattern.
Fibonacci was not the first to know about the sequence, it was known in India hundreds of years before!

His real name was Leonardo Pisano Bogollo, and he lived between 1170 and 1250 in Italy.
"Fibonacci" was his nickname, which roughly means "Son of Bonacci".
As well as being famous for the Fibonacci Sequence, he helped spread Hindu-Arabic Numerals (like our present numbers 0, 1, 2, 3, 4, 5, 6, 7, 8, 9) through Europe in place of Roman Numerals (I, II, III, IV, V, and so on). That has saved us all a lot of trouble! Thank you Leonardo.
Fibonacci Day is November 23rd, as it has the digits "1, 1, 2, 3" which is part of the sequence. So next Nov 23 let everyone know!